2x^2-9x+18=0

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Solution for 2x^2-9x+18=0 equation:


Simplifying
2x2 + -9x + 18 = 0

Reorder the terms:
18 + -9x + 2x2 = 0

Solving
18 + -9x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
9 + -4.5x + x2 = 0

Move the constant term to the right:

Add '-9' to each side of the equation.
9 + -4.5x + -9 + x2 = 0 + -9

Reorder the terms:
9 + -9 + -4.5x + x2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -4.5x + x2 = 0 + -9
-4.5x + x2 = 0 + -9

Combine like terms: 0 + -9 = -9
-4.5x + x2 = -9

The x term is -4.5x.  Take half its coefficient (-2.25).
Square it (5.0625) and add it to both sides.

Add '5.0625' to each side of the equation.
-4.5x + 5.0625 + x2 = -9 + 5.0625

Reorder the terms:
5.0625 + -4.5x + x2 = -9 + 5.0625

Combine like terms: -9 + 5.0625 = -3.9375
5.0625 + -4.5x + x2 = -3.9375

Factor a perfect square on the left side:
(x + -2.25)(x + -2.25) = -3.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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